Find t in a function when the ball hits the ground

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Hello everyone, I am having some problems solving this homework problem and was wondering if anybody can step me in the right direction.

The problem basically states that a ball is falling from a building at a speed of 8 ft/s and its position is detonated by s(t) = -16t^2-8t+66, where t is time. I need to find t when the ball touches the ground.

I've tried setting s(t) to 0 and factoring (because s(t) = 0 should mark when the ball is on the ground) but I've been unable to factor this equation.

Any help would be appreciated!
 
Hello, and welcome to FMH. I've marked your question unsolved, and edited the thread title to reflect that. :)

Your approach is correct:

[MATH]-16t^2-8t+66=0[/MATH]
I would nxt divide through by -2:

[MATH]8t^2+4t-33=0[/MATH]
This is not going to factor with rational roots, so try applying the quadratic formula, and discard the negative root. What do you find?
 
Thank you for the reply. Upon doing the quadratic formula:

-4 +- sqr(4^2 - 4(8)(-33)) -> -4 +- sqr(16 + 1056) -> 1.7963 (rounded) and -2.29625.
---------------------------- -----------------------
2(8) 16
Discarding the negative answer reveals the right answer for t to be 1.7963. Is this correct? I tried plugging it into my online math homework but it does not accept it.
 
Nevermind, I have figured it out. 1.7963 was the correct answer, but my math homework wanted me to write it as a fraction.

For those wondering how to do this (if they stumble upon this thread later):
-4 + sqr(16 + 1056) / 16 can be split into two fractions -4 / 16 and sqr(16 + 1056)/16. The first reduces to -1/4 and the second reduces to sqr(1072)/16, this makes your final answer be -1/4 + sqr(1072)/16
 
Yes, I got:

[MATH]t=\frac{-1+\sqrt{67}}{4}\approx1.79633819296811[/MATH]
This is equivalent to what you posted, just reduced.
 
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