"Find real numbers x and y such that x + y = 6 and xy = 7"
I setup a system of equations:
{x + y = 6
{xy = 7
solve for y by substitution:
x = (y - 6)
(y - 6)y = 7
-y^2 + 6y -7 = 0
I complete the square to get my too zeros: y = 3 + sqrt(2) and y = 3 - sqrt(2)
do I now plug in those two irrational values of y and solve for the two solutions of x?
Thanks, it's been a little while since I did this.
I setup a system of equations:
{x + y = 6
{xy = 7
solve for y by substitution:
x = (y - 6)
(y - 6)y = 7
-y^2 + 6y -7 = 0
I complete the square to get my too zeros: y = 3 + sqrt(2) and y = 3 - sqrt(2)
do I now plug in those two irrational values of y and solve for the two solutions of x?
Thanks, it's been a little while since I did this.