Find pt on 3 cos(x) where inst. rate of change is -1.5

babaoriley1981

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There is a point on the graph of f(x) = 3cosx (shown above) at which the instantaneous rate of change of f(x) is -1.5. Find the coordinates of that point.

can anyone help?
 
Re: really need help asap with calculus problem!

Hello, babaoriley1981!

There is a point on the graph of f(x)=3cosx\displaystyle f(x)\:=\:3\cdot\cos x (shown above)
at which the instantaneous rate of change of f(x)\displaystyle f(x) is 1.5\displaystyle \,-1.5
Find the coordinates of that point.

The instantaneous rate of change is given by the derivative: f(x)=3sinx\displaystyle \:f'(x)\:=\:-3\cdot\sin x

So we have:   3sinx=1.5        sinx=0.5        x=π6,5π6,\displaystyle \;-3\cdot\sin x\:=\:-1.5\;\;\Rightarrow\;\;\sin x\:=\:0.5\;\;\Rightarrow\;\;x\:=\:\frac{\pi}{6},\:\frac{5\pi}{6},\:\cdots

Since I can't see the graph from here,
. . you decide which value is appropriate.

 
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