Find k if: The roots are real and different. 3x^2 + 2x + k = 0
A alexs0uthern New member Joined Oct 22, 2014 Messages 2 Oct 22, 2014 #1 Find k if: The roots are real and different. 3x^2 + 2x + k = 0
pka Elite Member Joined Jan 29, 2005 Messages 11,988 Oct 22, 2014 #2 alexs0uthern said: Find k if: The roots are real and different. 3x^2 + 2x + k = 0 Click to expand... The discriminant, \(\displaystyle b^2-4ac\), is named that because it discriminates between the kinds of roots. If \(\displaystyle b^2-4ac>0\) there are two real roots.
alexs0uthern said: Find k if: The roots are real and different. 3x^2 + 2x + k = 0 Click to expand... The discriminant, \(\displaystyle b^2-4ac\), is named that because it discriminates between the kinds of roots. If \(\displaystyle b^2-4ac>0\) there are two real roots.
H HallsofIvy Elite Member Joined Jan 27, 2012 Messages 7,763 Oct 22, 2014 #3 Use the quadratic formula \(\displaystyle x= \frac{-b\pm\sqrt{b^2- 4ac}}{2a}\) The roots will be "real and different" if and only if the "discriminant", \(\displaystyle b^2- 4ac\) is positive.
Use the quadratic formula \(\displaystyle x= \frac{-b\pm\sqrt{b^2- 4ac}}{2a}\) The roots will be "real and different" if and only if the "discriminant", \(\displaystyle b^2- 4ac\) is positive.