mooshupork34
Junior Member
- Joined
- Oct 29, 2006
- Messages
- 72
Find the integral: int [ (e^x) / (e^(2x) - 9) ] dx.
First, I figured that e^(2x) is the same as (e^x)^2. Therefore, I changed the integrand to:
. . .(e^x) * ((e^x)^2 - 9)^(-1)
Using u-substitution, I then set u equal to e^x. Because dx is then equal to 1/(e^x) du, I multiplied that by the rest of the integral: e^x multiplied by 1 over itself cancels out, and I was left with:
. . .int [ ((u^2) - 9)^(-1) ] du
This is where I got stuck. Advice?
Thank you!
First, I figured that e^(2x) is the same as (e^x)^2. Therefore, I changed the integrand to:
. . .(e^x) * ((e^x)^2 - 9)^(-1)
Using u-substitution, I then set u equal to e^x. Because dx is then equal to 1/(e^x) du, I multiplied that by the rest of the integral: e^x multiplied by 1 over itself cancels out, and I was left with:
. . .int [ ((u^2) - 9)^(-1) ] du
This is where I got stuck. Advice?
Thank you!