f(x) = n if n ≤ x < n + 1 with n ∈ Z.
Determine (the integral from 0 to 4 of) (f(x)dx)
I couldn't find the symbol for the integral sry.
In the "header you wrote:
f(x)= n if n =< x > n + 1
But in your text, you wrote:
f(x) = n if n ≤ x < n + 1 with n ∈ Z.
Which one is correct?
What are your thoughts?
Please share your work with us ...even if you know it is wrong.
If you are stuck at the beginning tell us and we'll start with the definitions.
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f(x) = n if n ≤ x < n + 1 with n ∈ Z. This one is correct.
Actually i do not really have an idea how to start to solve the problem.
Start with the algebra you've learned:f(x) = n if n ≤ x < n + 1 with n ∈ Z.
Using the "area under the line" definition of the integral, drawing the four rectangles, and adding their areas, what value do you get?Determine (the integral from 0 to 4 of) (f(x)dx)
ks, Am I missing something or is this function defined for all reals? Please respond. Thanks!Well, let's try graphing the function and see what we get. The problem statement defines f(x) as:
\(\displaystyle f(x) = n \text{ if } n \le x \le n + 1\)
Considering now other information is given, I'll assume that the function is undefined everywhere else.
ksdhart2 overlooked the definition for n.ks, Am I missing something or is this function defined for all reals? Please respond. Thanks!
n ∈ Z
ksdhart2 overlooked the definition for n.
No biggie. We can constrain the domain of f, as you did, because the integral's bounds are 0 and 4.Yeah, I sure did. My mistake.