find horizontal, vertical asymptotes of (2x+3)/(x+2), if any

[Morgan_L1992]

ok heres the problem...i have no idea what to do because i have never before taken pre-calculus or the such i am just entering geometry and algerbra 2...here ya go...any help would be very much appreciated!!!

Find the horizontal and vertical asymptotes of the following. Type none if there isn't one.

f(x)=(2x+3)/(x+2)

yeah...i have no idea so can someone please help me....?

 

[galactus]

\(\displaystyle \L\\f(x)=\frac{2x+3}{x+2}\)

To find the vertical asymptote, what makes the denominator equal 0?.

For the horizontal asymptotes, there are some easy rules you can follow to see where they are, if any.

If the power of the numerator is equal to the power of the denominator, then the line \(\displaystyle y=\frac{a_{n}}{b_{k}}\)(ratio of leading coefficients) is the asymptote.

Your powers are equal. What's the ratio of the leading coefficients?.
(leading coefficient in numerator)/(leading coefficient in denominator).

Plus, graph it. That 'll help.

 

[skeeter]

Re: never taken pre-caclulus so i have no idea where to begi

ok heres the problem...i have no idea what to do because i have never before taken pre-calculus or the such i am just entering geometry and algerbra 2...

no idea? ... then go here and learn something about asymptotes.

 

[stapel]

i have no idea what to do because i have never before taken pre-calculus or the such i am just entering geometry and algerbra 2.

Wasn't this material covered in class...? :shock:

Eliz.