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Find foci of hyperbola
- Thread starter Xmatx5
- Start date
X^2/9 - y^2/4 = 1..... so I squared 9 and 4 which gave me 81 + 16.. which is 97. So c=square root of 97. And the foci I am getting is ( square root of 97, 0), and (- square root of 97,0).
Not quite right. The 9 and the 4 are already equal to a^2 and b^2; don't square them again.
Here is a useful site to check your work:
http://www.webmath.com/hyperbolas.html
So foci would equal square root of 13,0 and - square root of 13, 0?
Yes. See this site also for some nice examples and explanations:
http://www.purplemath.com/modules/hyperbola.htm