You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an alternative browser.
You should upgrade or use an alternative browser.
find foci of ellipse 9x^2+18sqrtx3+4y^2-16y+7=0, graph
- Thread starter leyva2389
- Start date
Find the foci for the ellipse 9x2+18√ ̅x3+4y2-16y+7=0 and graph the curve showing all pertinent data (ie vertices and foci).
leyva2389,
did you intend \(\displaystyle \ 9x^2 + 18x\sqrt{3} + 4y^2 - 16y + 7 = 0 \ ?\)
Assuming you get that sqrt(3) put in the right place, would the phrase "complete the square" give you a clue to get started?I basically am stuck all right from the start.
leyva2389,
did you intend \(\displaystyle \ 9x^2 + 18x\sqrt{3} + 4y^2 - 16y + 7 = 0 \ ?\)
My mistake. The problem correctly is...
9x2+18√3x+4y2-16y+7=0
Now that you have the sqrt(3) in the right place, doesthe phrase "complete the square" give you a clue to get started?My mistake. The problem correctly is...
9x2+18√3x+4y2-16y+7=0
The form of the equation for the ellipse that you want is
\(\displaystyle \displaystyle \dfrac {(x - x_0)^2}{a^2} + \dfrac {(y - y_0)^2}{b^2}\ =\ 1 \)
"A circle has no corners. An ellipse has no corners too, but not nearly as many no corners as much as a circle has."
Last edited:
Now that you have the sqrt(3) in the right place, doesthe phrase "complete the square" give you a clue to get started?
The form of the equation for the ellipse that you want is
\(\displaystyle \displaystyle \dfrac {(x - x_0)^2}{a^2} + \dfrac {(y - y_0)^2}{b^2}\ =\ 1 \)
"A circle has no corners. An ellipse has no corners too, but not nearly as many no corners as much as a circle has."
Okay so I work as far as I can get until I reach the radical when it comes to completing the square. I don't know what to do.
9(x2+2√ ̅3x+___)+4(y2-4y+___)=10
Does this mean that the cocktail hour started early today, and I missed the message?"A circle has no corners. An ellipse has no corners too, but not nearly as many no corners as much as a circle has."
Please try to make your postings legible.Okay so I work as far as I can get until I reach the radical when it comes to completing the square. I don't know what to do.
9(x2+2√ ̅3x+___)+4(y2-4y+___)=10
Do you know HOW to "complete the square" in the general case?
\(\displaystyle az^2 + bz + c = a(z + d)^2 + e.\)
If not, please say so.
If you do, I do not not understand what your mean by "until you reach the radical." The radical simply represents a real number.
Please try to make your postings legible.
Do you know HOW to "complete the square" in the general case?
\(\displaystyle az^2 + bz + c = a(z + d)^2 + e.\)
If not, please say so.
If you do, I do not not understand what your mean by "until you reach the radical." The radical simply represents a real number.
Yes, I know how to complete the square I just don't know if its the 2 or √ ̅3x that I complete for that particular part.
The coefficient of x is 2√ ̅3, and the coefficient of x^2 is a=1.Yes, I know how to complete the square I just don't know if its the 2 or √ ̅3x that I complete for that particular part.
Because you do not use parentheses, no one is completely sure whether you mean 18 * sqrt(3) * x or 18 * sqrt(3x).Yes, I know how to complete the square I just don't know if its the 2 or √ ̅3x that I complete for that particular part.
Assuming you mean
\(\displaystyle 9x^2 + (18\sqrt{3})x + 4y^2 - 16 y + 7 = 0\) then
\(\displaystyle 9\{(x^2 + (2\sqrt{3})x\} + 4\{y^2 - 4y\} = - 7.\)
How do you complete the square for \(\displaystyle ax^2 + bx,\) regardless of what a and b are?
In your case, what are a and b? So how do you complete the square?