y'=2cos(x)-xy^2 y(0)=1 y'(0)=1 y''(0)=0 y''= -2sinx - 2xyy' I can't calculate other derivatives
A a157 New member Joined Oct 17, 2020 Messages 7 Dec 6, 2020 #1 y'=2cos(x)-xy^2 y(0)=1 y'(0)=1 y''(0)=0 y''= -2sinx - 2xyy' I can't calculate other derivatives
D Deleted member 4993 Guest Dec 6, 2020 #2 a157 said: y'=2cos(x)-xy^2 y(0)=1 y'(0)=1 y''(0)=0 y''= -2sinx - 2xyy' I can't calculate other derivatives Click to expand... y''= -2sinx - 2xyy' ........................This is incorrect Try again - carefully - step by step
a157 said: y'=2cos(x)-xy^2 y(0)=1 y'(0)=1 y''(0)=0 y''= -2sinx - 2xyy' I can't calculate other derivatives Click to expand... y''= -2sinx - 2xyy' ........................This is incorrect Try again - carefully - step by step
R Romsek Senior Member Joined Nov 16, 2013 Messages 1,362 Dec 6, 2020 #3 Subhotosh Khan said: y''= -2sinx - 2xyy' ........................This is incorrect Try again - carefully - step by step Click to expand...
Subhotosh Khan said: y''= -2sinx - 2xyy' ........................This is incorrect Try again - carefully - step by step Click to expand...