find feasibility region of optimization eqn z = 6x + 10y

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Navyguy

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The maximum value of z = 6x + 10y has what feasible region?

My answer, after trying to work it out is, z = 130 at (x, y) = (8, 6). Is this right?

Thank you!
 
That's a tricky one, since it seems to be missing lots of information. Just guessing, it would seem that adding x>0 and y>0 might help you define a feasable region. On the other hand, you gain some for every x you give up for a y. You may wish to hang around the y-axis. On still another hand, there appear to be no upper limits on your definition of x and y. How does this result in ANY maximum value for z?

By the way, 6(8) + 10*(6) = 48 + 60 = 108
 
Navyguy said:
The maximum value of z = 6x + 10y has what feasible region?
Click to expand...
Infinitely-many, as posted.

You've had enough of these almost-identical exercises worked out for you, that you should be aware by now that you need to post the ENTIRE multiple-choice exercise for us to be able to help you.

Please reply with the answer options from which you are supposed to be choosing. When you reply, please show your work.

Thank you.

Eliz.
 
thanks TKHUNNY

thats what I had, i just wanted some one to check it for me, and there is always a different way to work it out. thanks again.
 
Navyguy said:
thats what I had
Click to expand...
Which is what you had? We weren't able to choose a feasibility region, because you didn't list them, and tutor tkhunny arrived at a different value of z from what you'd had.

Navyguy said:
i just wanted some one to check it for me, and there is always a different way to work it out.
Click to expand...
Since we don't know what the answer options were, and since you haven't shown your work, there is no way for us to "check it for" you. We might work it out differently, but we won't know that until you post your work and reasoning.

Thank you for your consideration.

Eliz.
 
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