find equation of a line tangent to f(x)=x3+x2+5x+2 at x=1 I completely forgot how to do this :(
A abbycookies New member Joined Apr 29, 2013 Messages 3 Apr 29, 2013 #1 find equation of a line tangent to f(x)=x3+x2+5x+2 at x=1 I completely forgot how to do this
D Deleted member 4993 Guest Apr 29, 2013 #2 abbycookies said: find equation of a line tangent to f(x)=x3+x2+5x+2 at x=1 I completely forgot how to do this Click to expand... 1) find the value f(1) 2) The line passes through [1, f(1)] 3) The slope of the line is the value of df/dx at x=1 4) Now you know a point on the line and its slope - determine the equation of the line.
abbycookies said: find equation of a line tangent to f(x)=x3+x2+5x+2 at x=1 I completely forgot how to do this Click to expand... 1) find the value f(1) 2) The line passes through [1, f(1)] 3) The slope of the line is the value of df/dx at x=1 4) Now you know a point on the line and its slope - determine the equation of the line.