so do i take the derivative of both sides? dy/dx = sec^2(xy) = 1 ???
M Marcia New member Joined Oct 18, 2005 Messages 14 Oct 18, 2005 #1 so do i take the derivative of both sides? dy/dx = sec^2(xy) = 1 ???
S soroban Elite Member Joined Jan 28, 2005 Messages 5,586 Oct 18, 2005 #2 Hello, Marcia! Given: tan(xy) = 1 Find: dy/dx at (π/4, 1) Click to expand... If you don't understand Implicit Differentiation, better read up on it. . . It's at least an hour-long lecture; we can't teach it to you here.
Hello, Marcia! Given: tan(xy) = 1 Find: dy/dx at (π/4, 1) Click to expand... If you don't understand Implicit Differentiation, better read up on it. . . It's at least an hour-long lecture; we can't teach it to you here.
