bballj228 said:
For the first one i got up to x + ?x = x^1/2 = x^3/2
How did you arrive at the conclusion that x[sup:38eapo7m]1/2[/sup:38eapo7m] somehow equalled x[sup:38eapo7m]3/2[/sup:38eapo7m]...? :shock:
bballj228 said:
2nd one 1(1-3x) - (-3)(3 + x) all over (1-3x)^2 = 10 / (1 - 3x) ^2
I will guess that the above means that "My derivative for the second function is..." as posted. If so, then your derivative expression is correct, but remember to format your answer intelligently before you hand it in. :wink:
bballj228 said:
3rd one i know its the quotient rule but not sure where to go with this one
I will guess that the above means that "I am fairly certain that finding the answer to Exercise (3) involves using the Quotient Rule, but I'm not sure how to do this."...?
You don't state how the function F(x) might relate to f(x), or how the derivative of F at x = a relates, so it is difficult to proceed. Since you applied the Quotient Rule in Exercise (2), obviously you know how to apply it to a rational function, so the difficulty must lie elsewhere, perhaps in the information (noted) which was omitted...?
bballj228 said:
For the fourth i tried the chain rule
?3x + 1 = 3x^1/2 + 1 = 1/2(3x)^1/2
I'm sorry, but I can't make heads or tails of this...? In addition to the missing information regarding F(x), f(x), and x = a, your string of "equalities" makes no sense. You have the function:
. . . . .\(\displaystyle f(x)\, =\, \sqrt{3}\, x \, +\, 1\)
Somehow, you ended up with:
. . . . .\(\displaystyle \sqrt{3}\, x \, +\, 1\, =\, 3\sqrt{x}\, +\, 1\, =\, \frac{1}{2} \sqrt{3x}\)
...which is obviously nonsense.
Please reply with the missing information, along with a
clear listing of your work and reasoning so far. This would include numbering, complete sentences, and explanations for your "equals" that aren't actually.
Thank you!
Eliz.