Find d/dx[x^x]
- Thread starter hank
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pka
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- Jan 29, 2005
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First of all, you must know that for \(\displaystyle x^x\) is defined only if \(\displaystyle x > 0.\)
That restriction means that you can use logarithms.
\(\displaystyle f(x) = x^x \quad \Rightarrow \quad f'(x) = \left( {x^x } \right)\left[ {\ln (x) + 1} \right].\)
That restriction means that you can use logarithms.
\(\displaystyle f(x) = x^x \quad \Rightarrow \quad f'(x) = \left( {x^x } \right)\left[ {\ln (x) + 1} \right].\)