Find Area of Rhombus?

I

iosman123

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Jul 25, 2019
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Hello,

What is the area of rhombus ABCD if AB = 13 inches and AC = 10 inches?

I was told to use the formula:

A = 1/2 TIMES (diagonal one * (diagonal two)) However, I cannot find the right answer.

thanks
iosman
 
iosman123 said:
Hello,

What is the area of rhombus ABCD if AB = 13 inches and AC = 10 inches?

I was told to use the formula:

A = 1/2 TIMES (diagonal one * (diagonal two)) However, I cannot find the right answer.

thanks iosman
Click to expand...
Rhombus has 4 equal sides. So either AC or AB is measure of diagonal.

Which is it?

Please share your work - with a sketch of ABCD attached - so that we know where does your mistake lie.....
 
I would assume if he rhombus is labelled conventionally, then AB is a side and AC is a diagonal. Is that correct, iosman?

Have you drawn a diagram?
Have you drawn in the other diagonal BD?
What is a special property of the diagonals of a rhombus?
Can you find the length of the diagonal BD?

Once you've answered those questions you should be able to put it together.
 
iosman123 said:
What is the area of rhombus ABCD if AB = 13 inches and AC = 10 inches?
A = 1/2 TIMES (diagonal one * (diagonal two)) However, I cannot find the right answer.
Click to expand...
Go to this LINK and use the diagram there.
In this problem \(\displaystyle \bf{a}=13\) because the diagonals are perpendicular bisectors of each other, \(\displaystyle |\overline{AS}|=5\).
With those two values you can find \(\displaystyle |\overline{DS}|=?\)
 
iosman123 said:
What is the area of rhombus ABCD if AB = 13 inches and AC = 10 inches?
Click to expand...

Ok i can imagine when we say ABCD this indicates AB is one of the sides and AC is the diagonal.
Now you probably know in rhombus , the two diagonals are perpendicular and cut each other in half. Now if you draw the two diagonals you will end up with 4 “———” triangles which then by knowing that they cut each other in half, you should be able to solve the problem.
 
ar of rhombus ==> 1/2(diag1*diag2)
point of intersection makes right angles
diag 1= 24
diag 2=32
ar == 1/2(32*24)
 
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