Find all x such that 9x^2 + 160x + 800 is perfect square.

[tony123]

If x is an integer, then find all integer x such that 9x^2+160x+800 is a perfect square.

 

[Denis]

9x^2 + 160x + 800 = a^2
9x^2 + 160x + 800 - a^2 = 0

Have you tried using the quadratic on this?

Anyway, there's 6 solutions; show what you tried...