I am looking for a bit of help completing 2 induction proofs of some Fibonacci identities.
1. (F[sub:8ov6t2og]0[/sub:8ov6t2og] )^2 + (F[sub:8ov6t2og]1[/sub:8ov6t2og])^2 + (F[sub:8ov6t2og]2[/sub:8ov6t2og] )^2 +. . . + (F[sub:8ov6t2og]n[/sub:8ov6t2og] )^2 = F[sub:8ov6t2og]n[/sub:8ov6t2og]*F[sub:8ov6t2og]n+1[/sub:8ov6t2og] . For n?0.
Thus far,
Basis is n=0, F[sub:8ov6t2og]0[/sub:8ov6t2og]^2 = 0 F[sub:8ov6t2og]0[/sub:8ov6t2og]*F[sub:8ov6t2og]1[/sub:8ov6t2og] = 0.
Induction hypothesis is n=k, (F[sub:8ov6t2og]0[/sub:8ov6t2og] )^2 + (F[sub:8ov6t2og]1[/sub:8ov6t2og])^2 + (F[sub:8ov6t2og]2[/sub:8ov6t2og] )^2 +. . . + (F[sub:8ov6t2og]k[/sub:8ov6t2og] )^2 = F[sub:8ov6t2og]k[/sub:8ov6t2og]*F[sub:8ov6t2og]k+1[/sub:8ov6t2og]
Induciton step is n=k+1, (F[sub:8ov6t2og]0[/sub:8ov6t2og] )^2 + (F[sub:8ov6t2og]1[/sub:8ov6t2og])^2 + (F[sub:8ov6t2og]2[/sub:8ov6t2og] )^2 +. . . + (F[sub:8ov6t2og]k[/sub:8ov6t2og] )^2 + F[sub:8ov6t2og]k+1[/sub:8ov6t2og] )^2
= F[sub:8ov6t2og]k+1[/sub:8ov6t2og]*F[sub:8ov6t2og]n(K+1)+1[/sub:8ov6t2og]
Then Substituting what we know from n=k, F[sub:8ov6t2og]k[/sub:8ov6t2og]*F[sub:8ov6t2og]k+1[/sub:8ov6t2og] + F[sub:8ov6t2og]k+1[/sub:8ov6t2og] )^2 = F[sub:8ov6t2og]k+1[/sub:8ov6t2og]*F[sub:8ov6t2og]n(K+1)+1[/sub:8ov6t2og]
And this is where I am not quit sure what to do?
Then 2.
F[sub:8ov6t2og]1[/sub:8ov6t2og] + F[sub:8ov6t2og]3[/sub:8ov6t2og] + F[sub:8ov6t2og]5[/sub:8ov6t2og] +. . . + F[sub:8ov6t2og]2n+1[/sub:8ov6t2og] = F[sub:8ov6t2og]2n+2[/sub:8ov6t2og] for n ?0.
So far,
Basis: n=0, F[sub:8ov6t2og]2*0+1[/sub:8ov6t2og] = 1 F[sub:8ov6t2og]2*0+2[/sub:8ov6t2og] = 1
Induction Hypothesis is n =k, F[sub:8ov6t2og]1[/sub:8ov6t2og] + F[sub:8ov6t2og]3[/sub:8ov6t2og] + F[sub:8ov6t2og]5[/sub:8ov6t2og] +. . . + F[sub:8ov6t2og]2k+1[/sub:8ov6t2og] = F[sub:8ov6t2og]2k+2[/sub:8ov6t2og]
Induction Step is n=k+1, F[sub:8ov6t2og]1[/sub:8ov6t2og] + F[sub:8ov6t2og]3[/sub:8ov6t2og] + F[sub:8ov6t2og]5[/sub:8ov6t2og] +. . . + F[sub:8ov6t2og]2(k+1)+1[/sub:8ov6t2og] = F[sub:8ov6t2og]2(k+1)+2[/sub:8ov6t2og]
The sub what we know from n=k,
F[sub:8ov6t2og]2k+2[/sub:8ov6t2og] + F[sub:8ov6t2og]2(k+1)+1[/sub:8ov6t2og] = F[sub:8ov6t2og]2(k+1)+2[/sub:8ov6t2og]
Again, Im just not sure where to go from.
Thank you
1. (F[sub:8ov6t2og]0[/sub:8ov6t2og] )^2 + (F[sub:8ov6t2og]1[/sub:8ov6t2og])^2 + (F[sub:8ov6t2og]2[/sub:8ov6t2og] )^2 +. . . + (F[sub:8ov6t2og]n[/sub:8ov6t2og] )^2 = F[sub:8ov6t2og]n[/sub:8ov6t2og]*F[sub:8ov6t2og]n+1[/sub:8ov6t2og] . For n?0.
Thus far,
Basis is n=0, F[sub:8ov6t2og]0[/sub:8ov6t2og]^2 = 0 F[sub:8ov6t2og]0[/sub:8ov6t2og]*F[sub:8ov6t2og]1[/sub:8ov6t2og] = 0.
Induction hypothesis is n=k, (F[sub:8ov6t2og]0[/sub:8ov6t2og] )^2 + (F[sub:8ov6t2og]1[/sub:8ov6t2og])^2 + (F[sub:8ov6t2og]2[/sub:8ov6t2og] )^2 +. . . + (F[sub:8ov6t2og]k[/sub:8ov6t2og] )^2 = F[sub:8ov6t2og]k[/sub:8ov6t2og]*F[sub:8ov6t2og]k+1[/sub:8ov6t2og]
Induciton step is n=k+1, (F[sub:8ov6t2og]0[/sub:8ov6t2og] )^2 + (F[sub:8ov6t2og]1[/sub:8ov6t2og])^2 + (F[sub:8ov6t2og]2[/sub:8ov6t2og] )^2 +. . . + (F[sub:8ov6t2og]k[/sub:8ov6t2og] )^2 + F[sub:8ov6t2og]k+1[/sub:8ov6t2og] )^2
= F[sub:8ov6t2og]k+1[/sub:8ov6t2og]*F[sub:8ov6t2og]n(K+1)+1[/sub:8ov6t2og]
Then Substituting what we know from n=k, F[sub:8ov6t2og]k[/sub:8ov6t2og]*F[sub:8ov6t2og]k+1[/sub:8ov6t2og] + F[sub:8ov6t2og]k+1[/sub:8ov6t2og] )^2 = F[sub:8ov6t2og]k+1[/sub:8ov6t2og]*F[sub:8ov6t2og]n(K+1)+1[/sub:8ov6t2og]
And this is where I am not quit sure what to do?
Then 2.
F[sub:8ov6t2og]1[/sub:8ov6t2og] + F[sub:8ov6t2og]3[/sub:8ov6t2og] + F[sub:8ov6t2og]5[/sub:8ov6t2og] +. . . + F[sub:8ov6t2og]2n+1[/sub:8ov6t2og] = F[sub:8ov6t2og]2n+2[/sub:8ov6t2og] for n ?0.
So far,
Basis: n=0, F[sub:8ov6t2og]2*0+1[/sub:8ov6t2og] = 1 F[sub:8ov6t2og]2*0+2[/sub:8ov6t2og] = 1
Induction Hypothesis is n =k, F[sub:8ov6t2og]1[/sub:8ov6t2og] + F[sub:8ov6t2og]3[/sub:8ov6t2og] + F[sub:8ov6t2og]5[/sub:8ov6t2og] +. . . + F[sub:8ov6t2og]2k+1[/sub:8ov6t2og] = F[sub:8ov6t2og]2k+2[/sub:8ov6t2og]
Induction Step is n=k+1, F[sub:8ov6t2og]1[/sub:8ov6t2og] + F[sub:8ov6t2og]3[/sub:8ov6t2og] + F[sub:8ov6t2og]5[/sub:8ov6t2og] +. . . + F[sub:8ov6t2og]2(k+1)+1[/sub:8ov6t2og] = F[sub:8ov6t2og]2(k+1)+2[/sub:8ov6t2og]
The sub what we know from n=k,
F[sub:8ov6t2og]2k+2[/sub:8ov6t2og] + F[sub:8ov6t2og]2(k+1)+1[/sub:8ov6t2og] = F[sub:8ov6t2og]2(k+1)+2[/sub:8ov6t2og]
Again, Im just not sure where to go from.
Thank you