fertilizer question

[bucknaged]

You have 20kg/ha for phosphorous and 60kg/ha for potassium

12.5-50-0 is $740/t and potash (0-0-60) is $600/t,
how much the fertilizer cost in acres?

I thought maybe it was something like

$740/1000*.50

 

[stapel]

You have 20kg/ha for phosphorous and 60kg/ha for potassium

I will guess that "ha" stands for "hectares". I will guess that, by "have", you mean "need".

12.5-50-0 is $740/t and potash (0-0-60) is $600/t,

I will guess that the strings of numbers separated by "minus" signs are actually the amounts of various chemicals, separated by hyphens. However, the chemicals indicated by the numbers have been omitted, as well as (I'm assuming) the name (analogous to "potash") preceding the first set of numbers.

I will guess that "t" means "ton" (English units) or "tonne" (metric units). However, any computation will require your specification of which type of units you mean (assuming my guess was correct).

how much the fertilizer cost in acres?

I will guess that, by "in acres", you mean "per acre".

I thought maybe it was something like

$740/1000*.50

I will guess that the instructions to the exercise directed you to determine how much of each fertilizer you should use, and to find the cost thereof. But what was the reasoning by which you arrived at the above expression?

When you reply, please also include the missing information, as noted above. Thank you.

 

[bucknaged]

Fertilizer question

I will guess that the strings of numbers separated by "minus" signs are actually the amounts of various chemicals, separated by hyphens. However, the chemicals indicated by the numbers have been omitted, as well as (I'm assuming) the name (analogous to "potash") preceding the first set of numbers.

I will guess that "t" means "ton" (English units) or "tonne" (metric units). However, any computation will require your specification of which type of units you mean (assuming my guess was correct).

I apologize for not being specific. The signs are hyphens. Yes, they are macro nutrients. The order is always Nitrogen, Phosphorous and Potassium.
The "T" stands for Tonnes. Yes, the question is asking for a per acre basis.

 

[stapel]

Is the following an accurate statement of the exercise?

Your fields require fertilization in the amounts of 20 kilograms of phosphorous per hectare and 60 kilograms of potassium per hectare. You have available to you two fertilizers, containing nitrogen (N), phosphorous (P), and potassium (K) in the following amounts:

. . . . .N-P-K: 12.5-50-0 (per metric tonne)
. . . . .N-P-K: 0-0-60 (per metric tonne)

The two fertilizers costs $740 and $600 per tonne, respectively. Determine from this information your per-acre cost of fertilizer.

If so, then you should start by determining how many tonnes of each you will need, per hectare. Fortunately, the two fertilizers do not overlap in the nutrients they provide, so you don't have any complicated computations. You need only consider the amounts of P and K.

You are given the percentages of P and K per 1000 kilograms. From this, multiply to find the number of kilograms of P and K per tonne, respectively, of each of the fertilizers.

You are given the numbers of kilograms of P and K needed per hectare. One hectare is about 2.471 acres. Convert the number of kilograms from "per hectare" to "per acre". This allows you to determine the fraction of a tonne (of each) needed per acre. From these fractional values, determine the cost of each. Sum to obtain the required value.

If you get stuck (or if I have guessed incorrectly), please reply showing your work. Thank you!