JackDaniels
New member
- Joined
- Oct 6, 2008
- Messages
- 2
Hi there, I have been banging my head against this problem for days...
The following identity is known as Fermat's Combinatorial Identity.
( n ) = SUM from i=k to n of (i-1)
( k ) (k-1)
give a combinatorial argument to establish this identity.
I know that ( n ) = (n-1) + (n-1)
( r ) (r-1) ( r ) , and that a way of thinking about this equation is that there are
(n-1) (n-1)
(r-1) groups with one chose object in it, and ( r ) groups without that same object.... but I am having trouble relating that knowledge to the above question.
Thanks in advance.
JD
The following identity is known as Fermat's Combinatorial Identity.
( n ) = SUM from i=k to n of (i-1)
( k ) (k-1)
give a combinatorial argument to establish this identity.
I know that ( n ) = (n-1) + (n-1)
( r ) (r-1) ( r ) , and that a way of thinking about this equation is that there are
(n-1) (n-1)
(r-1) groups with one chose object in it, and ( r ) groups without that same object.... but I am having trouble relating that knowledge to the above question.
Thanks in advance.
JD