Father and son problem

kingman

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I need help in the below problem
thanks

There are a father and a son. While the father covers 4 steps, the son covers 3 steps. The father covers a distance by 4 steps and the son covers the same distance by 5 steps. If the son covers 60 m, how many metres will the father cover?
 
I need help in the below problem
thanks

There are a father and a son. While the father covers 4 steps, the son covers 3 steps. The father covers a distance by 4 steps and the son covers the same distance by 5 steps. If the son covers 60 m, how many metres will the father cover?

Let's say that the father covers 4 steps in t seconds. The son would cover 3 steps in the same time, or t seconds.

With one step, the father covers x distance. With 4 steps, the father covers 4x distance.
With one step, the son covers y distance. With 5 steps, the son covers the same distance as the father, or 4x. hence, 5y = 4x; y = 4x/5

Distance covered by the father in T seconds = 60 m
t = 4 steps
1 = 4/t steps
T = 4T/t steps

The son would do [(4T/t)/4]*3 steps = 3T/t steps

The father does 60 m which is equivalent to (4T/t)x = 60
The son would cover (3T/t)y distance.

(3T/t)y = (3T/t)(4x/5)

(4T/t)x = 60

\(\displaystyle \dfrac{Tx}{t} = 15\)

\(\displaystyle (3T/t)(4x/5) = \dfrac{Tx}{t} \left(\dfrac{12}{5}\right) = 15 \left(\dfrac{12}{5}\right)\)

Does that make it a little easier maybe? It's a little difficult to explain over a post... Ask anything you're not sure about =]
 
need help

Let's say that the father covers 4 steps in t seconds. The son would cover 3 steps in the same time, or t seconds.

With one step, the father covers x distance. With 4 steps, the father covers 4x distance.
With one step, the son covers y distance. With 5 steps, the son covers the same distance as the father, or 4x. hence, 5y = 4x; y = 4x/5

Distance covered by the father in T seconds = 60 m
t = 4 steps
1 = 4/t steps
T = 4T/t steps

The son would do [(4T/t)/4]*3 steps = 3T/t steps

The father does 60 m which is equivalent to (4T/t)x = 60

The son would cover (3T/t)y distance.

(3T/t)y = (3T/t)(4x/5)

(4T/t)x = 60

\(\displaystyle \dfrac{Tx}{t} = 15\)

\(\displaystyle (3T/t)(4x/5) = \dfrac{Tx}{t} \left(\dfrac{12}{5}\right) = 15 \left(\dfrac{12}{5}\right)\)

Does that make it a little easier maybe? It's a little difficult to explain over a post... Ask anything you're not sure about =]



I try to follow you line of reasoning but could not get the answer of 100m
Please explain.
thanks
 
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