A rock is thrown vertically upwards from the edge of a cliff. It's height in feet measured above the ground at the base of the cliff, t seconds later, is given by the expression: y(t) = -16t^2 + 56t + 32
1) Compute the velocity of the rock using V(t) = lim [u->t] y(u)-y(t)/u-t
But wouldn't that equation equal 0?
2) When does the ball hit the ground, and what is the impact velocity at that instant?
3)When does the rock have a velocity of 0, and what happens to the rock at that instant?
Is the rock at its highest point when the velocity is zero? And is the answer to the last part of this that the rock begins to fall?
1) Compute the velocity of the rock using V(t) = lim [u->t] y(u)-y(t)/u-t
But wouldn't that equation equal 0?
2) When does the ball hit the ground, and what is the impact velocity at that instant?
3)When does the rock have a velocity of 0, and what happens to the rock at that instant?
Is the rock at its highest point when the velocity is zero? And is the answer to the last part of this that the rock begins to fall?