Facturing the difference of two cubes

[tmcintyre]

Hello,
My name is Tracy and I can't seem to figure out this problem, can you please help me?

8a^3-b^3= (2a-b^3)(4a^2+2a+b)
2a*4a^2= 8a^2
2a*2a=4a^2
2a*b=2ab
-b^3*4a^2=-4b^a^2
-b^3*2a=-2b^3a
-b^3*b+b3

 

[Aladdin]

Hello,
My name is Tracy and I can't seem to figure out this problem, can you please help me?

8a^3-b^3= (2a-b^3)(4a^2+2a+b)
2a*4a^2= 8a^2
2a*2a=4a^2
2a*b=2ab
-b^3*4a^2=-4b^a^2
-b^3*2a=-2b^3a
-b^3*b+b3

hey there.
Rule: (-a-b)^3=-a^3-3a^2b-3ab^2-b^3

And a^3 - b^3 = (a - b)(a2 + ab + b2)


So:8a^3-b^3=(2a-b)(4a^2+2ab+b^2) This is Factorization

 

[Denis]

2a*4a^2= 8a^2

Got no idea what you're trying to do!
Anyway, 2a * 4a^2 = 8a^3

 

[tmcintyre]

Thank you Aladdin, that really helped me.

 

[Aladdin]

Thank you Aladdin, that really helped me.

Its my pleasure . hoping u will do me a favor back