The question is: Factor 1331m3n9 - 125p6.
I have never factored an equation like this... Help would be greatly appreciated!
Thanks!
Hint:
a3- b3 = (a-b)(a2 + ab + b2)
a2 - b2 = (a + b)(a - b)
[Is] this [factorization] correct?
1331m3n9-125p6 = (11mn3 - 5p2)(121m2n6 + 55mn3p2 + 25p4)
Yes -- good job! :cool:
is it fully factored?
Cannot be further factor with integer coefficients and exponents.Yes.
None of the basic factoring patterns can be further factored. If they could, why teach them? :cool: