factoring to the 4th power

[seanwilliam]

Hi all,

This one has me beaten,

Factor the expression

x^4+27x

Any ideas?

 

[pka]

This one has me beaten,
Factor the expression
x^4+27x

\(\displaystyle x^4+27x=x(x^3+27)=x(x^3+3^3)\). That last factor is the sum of two cubes.

 

[seanwilliam]

Aaah!

So its x(x+3)(x^2-3x+9) !

Thanks for the help all!