Could someone please show me how to factor x to 5 power, 2x to third power, minus x squared, minus 2
R rafirank New member Joined Jun 16, 2013 Messages 5 Jun 29, 2013 #1 Could someone please show me how to factor x to 5 power, 2x to third power, minus x squared, minus 2
mmm4444bot Super Moderator Joined Oct 6, 2005 Messages 10,962 Jun 29, 2013 #2 Is this homework? What methods have you seen? For example, have you learned about roots of polynomials? Or, have you used the Remainder Theorem or the Factor Theorem? Can you do polynomial long division or synthetic division? Did you try any stuff? Where are you stuck? If you need links to lessons on the topics above, please let us know. Cheers :cool: PS: This is how we text polynomials, x^5 + 2x^3 - x^2 - 2
Is this homework? What methods have you seen? For example, have you learned about roots of polynomials? Or, have you used the Remainder Theorem or the Factor Theorem? Can you do polynomial long division or synthetic division? Did you try any stuff? Where are you stuck? If you need links to lessons on the topics above, please let us know. Cheers :cool: PS: This is how we text polynomials, x^5 + 2x^3 - x^2 - 2
R rafirank New member Joined Jun 16, 2013 Messages 5 Jun 30, 2013 #3 I don't know how to get the arrow pointing up and yes I do know how to factor polynomials but I am just stuck on this one.
I don't know how to get the arrow pointing up and yes I do know how to factor polynomials but I am just stuck on this one.
mmm4444bot Super Moderator Joined Oct 6, 2005 Messages 10,962 Jun 30, 2013 #5 rafirank said: I do know how to factor polynomials but I am just stuck on this one. Click to expand... Okay, so you have factored higher-order polynomials before, but you got stuck somewhere on this exercise. Please show us what you tried. Here is a link to a summary of the posting guidelines.
rafirank said: I do know how to factor polynomials but I am just stuck on this one. Click to expand... Okay, so you have factored higher-order polynomials before, but you got stuck somewhere on this exercise. Please show us what you tried. Here is a link to a summary of the posting guidelines.
S soroban Elite Member Joined Jan 28, 2005 Messages 5,586 Jul 1, 2013 #7 Hello, rafirank! \(\displaystyle \text{Factor: }\: x^5 + 2x^3 - x^2 - 2\) Click to expand... \(\displaystyle x^5 + 2x^3 - x^2 - 2 \;=\;x^3(x^2+2) - 1(x^2+2)\) . . . . . . . . . . . . . . \(\displaystyle =\; (x^2+2)(x^3-1)\) . . . . . . . . . . . . . . \(\displaystyle =\; (x^2+2)(x-1)(x^2+x+1)\)
Hello, rafirank! \(\displaystyle \text{Factor: }\: x^5 + 2x^3 - x^2 - 2\) Click to expand... \(\displaystyle x^5 + 2x^3 - x^2 - 2 \;=\;x^3(x^2+2) - 1(x^2+2)\) . . . . . . . . . . . . . . \(\displaystyle =\; (x^2+2)(x^3-1)\) . . . . . . . . . . . . . . \(\displaystyle =\; (x^2+2)(x-1)(x^2+x+1)\)
R rafirank New member Joined Jun 16, 2013 Messages 5 Jul 1, 2013 #8 Thank you everyone. I got the answer. Rafi
L lookagain Elite Member Joined Aug 22, 2010 Messages 3,251 Jul 1, 2013 #9 Denis said: x^5 + 2x^3 - x^2 - 2 Why not this simple: x^3(x^2 + 2) - (x^2 + 2) (x^2 + 2)(x^3 - 1) Click to expand... What you wrote isn't fully factored over rational coefficients.
Denis said: x^5 + 2x^3 - x^2 - 2 Why not this simple: x^3(x^2 + 2) - (x^2 + 2) (x^2 + 2)(x^3 - 1) Click to expand... What you wrote isn't fully factored over rational coefficients.