ccsafetylady
New member
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- May 21, 2007
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The direction is to Factor Completely. Can anyone verify that this is correct?
x^21 + y^24 = (x^7-y^8)(x^14+x^7y^8-y^16)
x^21 + y^24 = (x^7-y^8)(x^14+x^7y^8-y^16)
Factoring Powers: x^21 + y^24 = (x^7-y^8)(x^14+x^7y^8-y^16)
- Thread starter ccsafetylady
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- Feb 4, 2004
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Applying the sum-of-cubes formula to (x<sup>7</sup>)<sup>3</sup> + (y<sup>8</sup>)<sup>3</sup> would be what I'd do. And I don't see any further factoring being possible with the two factors you end up with, so my guess is that, once you correct your signs, you're done! 
Eliz.
Eliz.