factoring polynomials

[kramer65gto]

x^2+6x-y^2+9
x(x+6)-(y^2-9)
x(x+6)-(y+3)(y-3)


Is this problem finished?

problem #2
64p^4 -p
p(64p^3-1)
p(2p)^3-1

I need assistance please
Thanks

 

[pappus]

x^2+6x-y^2+9
x(x+6)-(y^2-9)
x(x+6)-(y+3)(y-3) <--- you didn't factor the polynomal


Is this problem finished?

problem #2
64p^4 -p
p(64p^3-1)
p((2p)^3-1) <-- don't forget the brackets!

I need assistance please
Thanks

Here is what I would have done:

\(\displaystyle x^2+6x-y^2+9 = (x^2+6x+9)-y^2 = \underbrace{(x+3)^2-y^2}_{\text{difference of squares}} \)\(\displaystyle = (x+3+y)(x+3-y)\)

To the 2nd problem: You should know that \(\displaystyle x^3-1 = (x-1)(x^2+x+1)\)