factoring polynomials: 4m^4n^2 + 4m^3n^2 + m^2n^2

jgoldfield

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Sep 6, 2006
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Alright so, I'm not that great at factoring and I have to do a bunch of problems with factoring each polynomial completely. I did around half (basically all the easier ones) but there are a lot left that I can't do without spending a Lot of time on.

Here's an example: 4m^4n^2 + 4m^3n^2 + m^2n^2

I'd appreciate your help,
Thanks,
J
 
Hello jg.

Factor out the \(\displaystyle n^{2}m^{2}\)

\(\displaystyle n^{2}(4m^{2}+4m+1)n^{2}\)

Now, factor what's inside the parentheses:

\(\displaystyle 4m^{2}+4m+1=(2m+1)^{2}\)

You end up with:

\(\displaystyle \L\\n^{2}(2m+1)^{2}m^{2}\)

See?.
 
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