Can this polynomial expression be factored? . . .8x^3 - 29
D Danny Ingram New member Joined Jan 31, 2007 Messages 2 Jan 31, 2007 #1 Can this polynomial expression be factored? . . .8x^3 - 29
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,582 Jan 31, 2007 #2 Are you sure the last term is "29", and not "27"? Thank you. Eliz.
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,216 Jan 31, 2007 #3 Not nicely. You could write: \(\displaystyle \L\\(2x)^{3}-(29^{\frac{1}{3}})^{3}\) Then factor difference of two cubes: \(\displaystyle \L\\(2x-29^{\frac{1}{3}})(4x^{2}+2x\cdot{29^{\frac{1}{3}}}+29^{\frac{1}{3}})\)
Not nicely. You could write: \(\displaystyle \L\\(2x)^{3}-(29^{\frac{1}{3}})^{3}\) Then factor difference of two cubes: \(\displaystyle \L\\(2x-29^{\frac{1}{3}})(4x^{2}+2x\cdot{29^{\frac{1}{3}}}+29^{\frac{1}{3}})\)
