Factoring into linear or irreducible quadratic factors

[jbauman793]

I don't rember how to factor:

x^3-27

into this form (___)(______)

 

[BigGlenntheHeavy]

$\displaystyle a^3-b^3 \ = \ (a-b)(a^2+ab+b^2)$

 

[jbauman793]

x^3+6x^2+12x+8=(__)(____)=(__)^3

Okay I understand the a and b parts. but with this one i don't know what to do. my friend said that the final answer is x+2^3.

 

[Deleted member 4993]

x^3+6x^2+12x+8=(__)(____)=(__)^3

Okay I understand the a and b parts. but with this one i don't know what to do. my friend said that the final answer is (x+2)^3.

$\displaystyle (a + b)^3 \ = \ a^3 \ + \ b^3 \ + \ 3a^2b \ + \ 3ab^2$

These formula should be crammed - tattooed on your forehead - never to be forgotten.