jbauman793
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- Aug 6, 2010
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I don't rember how to factor:
x^3-27
into this form (___)(______)
x^3-27
into this form (___)(______)
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Factoring into linear or irreducible quadratic factors
- Thread starter jbauman793
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BigGlenntheHeavy
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\(\displaystyle a^3-b^3 \ = \ (a-b)(a^2+ab+b^2)\)
jbauman793
New member
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- Aug 6, 2010
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- 13
x^3+6x^2+12x+8=(__)(____)=(__)^3
Okay I understand the a and b parts. but with this one i don't know what to do. my friend said that the final answer is x+2^3.
Okay I understand the a and b parts. but with this one i don't know what to do. my friend said that the final answer is x+2^3.
D
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jbauman793 said:x^3+6x^2+12x+8=(__)(____)=(__)^3
Okay I understand the a and b parts. but with this one i don't know what to do. my friend said that the final answer is (x+2)^3.
\(\displaystyle (a + b)^3 \ = \ a^3 \ + \ b^3 \ + \ 3a^2b \ + \ 3ab^2\)
These formula should be crammed - tattooed on your forehead - never to be forgotten.