FACTORING BY GROUPING HELP PLEASE!!

PreAlgebraDummy15

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5x<sup>4</sup> -80

5(1x<sup>3</sup>-16) 5(1x<sup>3</sup>+16)


Is that the right answer? I factored 5 & 80 by 5 (5 goes into 5 once and 5 goes into 80 16 times. ) Thanks!
 
PreAlgebraDummy15 said:
5x<sup>4</sup> -80

5(1x<sup>3</sup>-16) 5(1x<sup>3</sup>+16)


Is that the right answer? I factored 5 & 80 by 5 (5 goes into 5 once and 5 goes into 80 16 times. ) Thanks!
NO! See my answer to your other SAME post.

That answer you show indicates that you're NOT ready for this
kind of factoring: you need to go back to basics :!:
 
PreAlgebraDummy15 said:
5x<sup>4</sup> -80

5(1x<sup>3</sup>-16) 5(1x<sup>3</sup>+16)


Is that the right answer? I factored 5 & 80 by 5 (5 goes into 5 once and 5 goes into 80 16 times. ) Thanks!
What? Too much going on. It's simpler than you are making it.

5x<sup>4</sup> - 80 =
Factoring out the 5 using the Distributive Property of Multiplication over Addition
5*(x<sup>4</sup> - 16) =
Difference of Squares
5*(x<sup>2</sup> - 4)*(x<sup>2</sup> + 4) =
Difference of Squares
5*(x + 2)*(x - 2)*(x<sup>2</sup> + 4)

One piece at a time.

Learn the Distributive Property of Multiplication over Addition. This will prevent you from inventing new '5's.

Memorize the form "Difference of Squares". You will see this often.
 
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