factoring 3x^2-10x+7: no GCF, so what do I do?

Re: factoring again....

spicytakoyum said:
3x^2-10x+7

Since there is no GCF, what do I do?

Thank you

Use the grouping method like I showed in your last post. For ax^2 + bx + c, find two numbers p,q, such that p + q = b, and (ac) / (p + q) is a whole number: ie: find two numbers that add up to b and are also divisible by a*c. Replace bx by the two terms and then group the trinomials into the sum of two binomials... factor out terms from each binomial, simplify.

John
 
3x^2-10x+7 = (3x - __)(x - __)

Fill in the blanks so that when you multiply the binomials together, you get the original trinomial. There is only one combination of numbers that works.
 
spicytakoyum said:
Since there is no GCF, what do I do?
There are many methods taught for factoring quadratics. If the method(s) they covered in your class and in your textbook is/are not working for you, then try one or another of the methods taught online! :idead:

Eliz.
 
Top