Re: Factoring?!?!?
Yes, factor out the 2 and then use the sum of two cubes factorization, \(\displaystyle (x+y)(x^{2}-xy+y^{2})\).
\(\displaystyle 2(x^{3}+125)\)
\(\displaystyle 2(x^{3}+(5)^{3})\)
....\(\displaystyle \uparrow\ \;\ \nearrow\)
....\(\displaystyle \text{x} \;\ \text{y}\)
Now, finish?.