Factor out completely 24x^2 - 10x - 4

G

Guest

Guest
24x^2 - 10x - 4

I chose 2 as the GCF so

2(12x^2 - 5x - 2)

Now this where I am stunned is this completely factored or is there more to it?
Maybe I just done the whole thing wrong. Someone please help me here.
 
You did the first step correctly: you factored out the "2" that was common to all three terms of the quadratic. Now you need to factor the remaining quadratic.

Has factoring quadratics been covered in class? If so, what method have you learned for factoring trinomials? If not, please specify, so we can provide links to online lessons on this topic.

Thank you.

Eliz.
 
Yes, it has but there is many different ways and I can't figure out which one to use.

Its different formulas:

Special Product Formula- (x+y)(x+y)= x^2 +2xy +y2 and (x-y)(x-y)= x^2 - 2xy+y^2.

Factoring with the coefficients of 1 - (x+a)(x+b)

Factoring with coefficients other than 1- (ax+b)(cx+d)

Testing for factorability: b^2 - 4ac

Product-sum formula: example: x^2 - 9x + 20 you see what the product of 20 is and when you add them together you get -9

Maybe this will help out on which one I should use.

Thanks
Leslie
 
Keep it simple, Les me lad; your equation: 24x^2 - 10x - 4
Divide by 2:
12x^2 - 5x - 2
Now factor that; use the quadratic to get x = 2/3 or x = -1/4;
use that to factor...ok?
 
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