faces of cubical die labelled w/ primes. find prob that....

Nekkamath

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The faces of a cubical die are each labeled with a different prime number, and each of the six smallest prime numbers (2,3,5,7,11,13) is on exactly one face of the die. The die will be rolled twice. What is the probability that the product of the two numbers rolled will be even? Express you answer as a common fraction.

I saw that there were 6 favorable outcomes when multiplying all numbers by 2. I mulitiplied 6 die numbers by 6 to get 36 possible outcomes. So I came up with 6/36 which is 1/6.
 
Nekkamath said:
The faces of a cubical die are each labeled with a different prime number, and each of the six smallest prime numbers (2,3,5,7,11,13) is on exactly one face of the die. The die will be rolled twice. What is the probability that the product of the two numbers rolled will be even? Express you answer as a common fraction.
Draw a six-by-six grid. Label along the left-hand side and across the top with the values of the various faces. Fill in the grid with the products of the row and column labels.

You will end up with thirty-six values. Of these, how many are even?

Eliz.
 
Nekkamath said:
The faces of a cubical die are each labeled with a different prime number, and each of the six smallest prime numbers (2,3,5,7,11,13) is on exactly one face of the die. The die will be rolled twice. What is the probability that the product of the two numbers rolled will be even?
There are thirty-six outcomes: ordered pairs.
Of those, these are favorable: (2,2), (2,3), (2,5), (2,7), (2,11), (2,13), (3,2), (5,2), (7,2), (11,2), & (13,2).
 
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