f'(x)

amy2310 said:
f(x)=sqroot x+1: x=3
Click to expand...
Are we just evaluating?

f(3) = sqrt(3+1) = sqrt(4) = 2

Maybe a derivative evaluated at x = 3?

f'(x) = 1/[2*sqrt(x+1)]
f'(3) = 1/[2*sqrt(3+1)] = 1/4

It is very difficult to help you if you do not:
1) Give the actual problem statement.
2) Show your work.
 
Sorry find the given f'(x) when x has the given value this is how I worked it

sqroot (x+1) x=3
sqroot 4(1/2)

I see i did not work that right
 
f(x) = sqrt(x+1) = (x+1)^(1/2)

To find f'(x), apply the chain rule.

Once you have f'(x), substitute x=3 into it.
 
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