f(x) = cos( [ {g(x)^2 }] + e^{sq (g(x))}

[Sophie]

Please please could someone explain the question...

I have spent a week trying to understand the following style of questions. My problem is I just do not understand what is being asked of me. I am getting frustrated as I understand everything else in this section and do not want to move on until I understand the following, although I might just have to. I answered using an example of a question that was similar but not the same.

Question: Write f' in terms of g' simplify your answer.

I did the following...


\(\displaystyle \L\\\begin{array}{l}
f(x) = \cos \left( {\left[ {g(x)} \right]^2 } \right) + e^{\sqrt {^{g(x)} } } \\
f'(x) = - \sin \left( {\left[ {g(x)} \right]^2 } \right)2g(x)g'(x) + e^{\sqrt {^{g(x)} } } \frac{1}{2}\left( {g(x)} \right)^{ - 1/2} g'(x) \\
f'(x) = g'(x)\left( { - \sin \left( {\left[ {g(x)} \right]^2 } \right)2g(x) + \frac{{e^{g(x)} }}{{2\sqrt {g(x)} }}} \right) \\
\end{array}\)


Please please could someone explain what is being asked of me, thanks Sophie

 

[pka]

It seems to me that you have answered the question.
Why do you think otherwise?

 

[Sophie]

Thanks for the reply. I am very surprised I am right. I normally feel positive about what I am doing and understand it, especially when I spend so long trying and in this case I did not. Unfortunately this just threw me, however it looks like I have spent a lot of time figuring something out I had right the 1st time. Other questions similar to this were worded in such a way I understood what was being asked.

Thanks again, Sophie