f(x)=3x^2-3, g(x)=1-x

[Kogsug]

can someone help me with the last step
f(x)=3x^2-3, g(x)=1-x find f(f(x))

i did

F(g(x))=3(g(x))^2-3

=3(1-x)^2-3

the next step im confused about.

its written as

-3x^2-6x

why is it -3? shouldnt it start out with 3x^2-6x?

its already done by somone else but i dont know if its right.

thank you

 

[Unco]

You're spot on, Kogsug. You can have that person's slice of carrot cake.

 

[Kogsug]

You're spot on, Kogsug. You can have that person's slice of carrot cake.

What do you mean???

You didnt asnwer my question.
:?: :?: :?: :?:

 

[pka]

\(\displaystyle \L
\begin{array}{l}
f(x) = 3x^2 - 3\quad \& \quad g(x) = 1 - x \\
f(g(x)) = 3\left( {1 - x} \right)^2 - 3\quad \& \quad g(f(x)) = 1 - \left( {3x^2 - 3} \right) \\
\end{array}\)

 

[Kogsug]

ok thank you