f(x)=-1/4(x^5+2x^4-15x^3-40x^2+4x+48)

[dani143]

ok so i plug in numbers at f(x) and after finding F(x)=0
i got the x-intercepts which are x=3(order2), -2(iorder2), and -1
my y-intercept is -9 by plugging x=0


the increase is xE(-2,-1.5)u(1,3)
the decrease is xE(-1.5,1)u(3,infinity)

positive(above x-axis|) are xE(-infinity,-1)
negative (below x-axis) are xe(-1,infinity)

i dont know the slope of function... all i know is slope is y=delta y/ delta x

please help with findin the functions symmetry and slope.. thank you

 

[stapel]

Does the following exercise refer to the function in the subject line? If so, what were the instructions for this function? What are you supposed to be doing with it? If not, what are you doing in your post?

With respect to the function in the subject line, the function appears to be as follows:

. . . . .\(\displaystyle f(x)\, =\, \frac{-1}{4(x^5\, +\, 2x^4\, -\, 15x^3\, -\, 40x^2\, +\, 4x\, +\, 48)}\)

But some of your working suggests that this might not be what you meant. Please confirm or correct.

i dont know the slope of function... all i know is slope is y=delta y/ delta x

To find the intervals of increase and decrease, and to find the equation of the "slope" at points, take the derivative.

please help with findin the functions symmetry

To investigate symmetry, try looking at the graph.