extreme values of x^2 y when x >= 0 and y <= 0

[dbob85]

Under the condition that 2x - 5y = 18, minimize x^2y when x > 0 and y < 0

 

[stapel]

This works very much like the other exercise. Where are you stuck? You solved "2x - 5y = 18" for one of the variables (probably y), plugged this in for that variable in "x²y", took the derivative, and... then what?

Please reply showing all of your steps. Thank you.

Eliz.