Extra credit word problem

[K-man]

This word problem seems very straight forward but I have not been able to figure it out- help...

Find the fraction which is equivalent to 3/7 such that when the numerator is doubled and the denominator is increased by 20, the result equals 2/3

 

[Deleted member 4993]

This word problem seems very straight forward but I have not been able to figure it out- help...Find the fraction which is equivalent to 3/7 such that when the numerator is doubled and the denominator is increased by 20, the result equals 2/3

LetThe fraction = x/y

Then

the fraction which is equivalent to 3/7 →

x/y = 3/7 ........................................................................................................ (1)

the numerator is doubled and the denominator is increased by 20, the result equals 2/3 →

(2*x)/(y+20) = 2/3 ...........................................................................................(2).....edited

Now continue.....