Jormungand
New member
- Joined
- Sep 21, 2009
- Messages
- 1
I have a question that I seem to be stuck on.
Backround information includes: I have a pentagon inscribed in a circle. No circumference, no radius is given.
Pentagon = 5 sides which means we have 10 interior angles (10 right triangles = Pentagon)
I found the area of my Pentagon to be A=5r^2(Sin36)(Cos36)
I then found the area of a "n-gon" to be: A=nr^2(Sin360/2n)(Cos360/2n) Where n = number of sides and 2n = number of angles.
So...
My question reads:
"If y=kx^2, we say that y varies directly with the square of x where k is the variation constant. Express the result of part b in these terms."
And ofcourse the results of part b is: A=nr^2(Sin360/2n)(Cos360/2n)
n = number of sides, 2n = number of angles.
The result of the part b is the area of a "n-gon" in terms of r and n.
I am stuck on how I can take the results of part b and express it in terms of y=kx^2
If anyone can help me that would be greatly appreciated!!!
Thank you!
Backround information includes: I have a pentagon inscribed in a circle. No circumference, no radius is given.
Pentagon = 5 sides which means we have 10 interior angles (10 right triangles = Pentagon)
I found the area of my Pentagon to be A=5r^2(Sin36)(Cos36)
I then found the area of a "n-gon" to be: A=nr^2(Sin360/2n)(Cos360/2n) Where n = number of sides and 2n = number of angles.
So...
My question reads:
"If y=kx^2, we say that y varies directly with the square of x where k is the variation constant. Express the result of part b in these terms."
And ofcourse the results of part b is: A=nr^2(Sin360/2n)(Cos360/2n)
n = number of sides, 2n = number of angles.
The result of the part b is the area of a "n-gon" in terms of r and n.
I am stuck on how I can take the results of part b and express it in terms of y=kx^2
If anyone can help me that would be greatly appreciated!!!
Thank you!