exponents in equations

Luanne

New member
Joined
Apr 9, 2007
Messages
4
can someone help me solve this problem

solve for (x,y) if: 2^x * 4^(2y)=64
4^(2x) * 2^y=8[/list][/code]
 
\(\displaystyle \L\begin{array}{l}
\left( {2^x } \right)\left( 4 \right)^{2y} = \left( {2^x } \right)\left( {2^2 } \right)^{2y} = \left( {2^x } \right)\left( {2^{4y} } \right) = 2^{x + 4y} \\
\left( 4 \right)^{2x} \left( {2^y } \right) = \left( {2^2 } \right)^{2x} \left( {2^y } \right) = \left( {2^{4x} } \right)\left( {2^y } \right) = 2^{4x + y} \\
\end{array}\)
 
Top