exponents and radicals (rational)

The weight of an object on the Earth’s surface varies inversely with the square of its distance from the center of the Earth. An object weighs 1000 pounds on the Earth’s surface. This is approximately 4000 miles from the center of the Earth. How much would an object weigh 4500 miles from the center of the Earth. Round the answer to the nearest pound.


This time your starting equation is:

W = k*(1/r^2)

As in the other problem, plug in your first set of values and solve for k. Then you can answer the final problem question.
 
Inverse means one thing changes the opposite way anothe thing changes.

If something gets bigger, then something else gets smaller...and so forth.

What this is saying is that the further you go from the Earth, the lighter

you become. Weight is inversely proportional to the square of the

distance means as the distance(and thus the square of the distance) gets

larger, the weight gets smaller. You know that already. It's common

knowledge that if you go into outer space you'll float around. Right?.

When you set up proportions, find the value of k first using the initial

conditions given, then sub it into the formula.


\(\displaystyle y=\frac{k}{x}\)

Find k.

\(\displaystyle 1000=\frac{k}{4000^{2}}\)

Now, solve for k and divide it by \(\displaystyle 4500^{2}\)


You could just set it up as:

\(\displaystyle \frac{x}{4000^{2}}=\frac{1000}{4500^{2}}\), solve for x.
 
It's common knowledge that if you go into outer space you'll float around. Right?

:x wrong ... you're not "floating", you're falling.

common knowledge is oft times lacking. :wink:
 
Yes, I reckon you're right, skeeter. I stand corrected. You know what I

meant, though.

Apparently, it makes no difference. For whatever reason, buttonnose

deleted the original post.
 
ButtonNose said:
Why are you deleting your questions? Were you not allowed to get help with this? Was this a take-home test, and you were on the honor system to do it yourself?

Eliz.
 
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