Exponential System: 100 = ab^3, 197 = ab^2

strato

New member
Joined
Jun 11, 2007
Messages
3
I have no idea how to solve this problem:

100=ab^3
197=ab^2

I need to find a and b in order to write an exponential equation. So far, I have this: y=a(b^x) +3

I really need help with this ASAP!
 
There's different ways to proceed, but did you try the ol' substitution method?.

Solve the first for \(\displaystyle a=\frac{100}{b^{3}}\)

Sub into the second and solve for b.
 
That didn't work for me because the graph is exponential decay. Sorry for the mistake, but the equation I have so far is actually: y=a(b^-x) +3. The graph needs to be entirely positive, as I am dealing with a position vs. time graph.
 
Re: Exponential Systems

strato said:
100=ab^3
197=ab^2
Or simply do a division:

100=ab^3
=======
197=ab^2

100 / 197 = b

Now go get a !
 
Top