Exponential problem: (x+2)^3/4 = 27

[Guest]

So the problem is: (x+2)^3/4 = 27

I know that the four can be the square root of x+2 but I don't see how this helps any in solving the problem. Help?

 

[galactus]

Is that \(\displaystyle (x+2)^{\frac{3}{4}}=27\)

or

\(\displaystyle \frac{(x+3)^{3}}{4}=27\)?


If it's the first: \(\displaystyle (x+2)=27^{\frac{4}{3}}\)

\(\displaystyle x=27^{\frac{4}{3}}-2\)


If it's the second: \(\displaystyle (x+2)^{3}=108\)

\(\displaystyle (x+2)=(108)^{\frac{1}{3}}\)

\(\displaystyle x=(108)^{\frac{1}{3}}-2\)

 

[Guest]

It was the first one and thanks! I didn't even think about doing it that way. And sorry bout the equation, couldn't think of another way to write it, lol.

 

[stapel]

couldn't think of another way to write it

Use grouping symbols, such as:

. . . . .(x + 2)^(3/4) = 27

...as opposed to:

. . . . .[(x + 2)^3] / 4 = 27

Then your meaning is clear.

Thank you.

Eliz.