Exponential problem: (x+2)^3/4 = 27

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So the problem is: (x+2)^3/4 = 27

I know that the four can be the square root of x+2 but I don't see how this helps any in solving the problem. Help?
 
Is that (x+2)34=27\displaystyle (x+2)^{\frac{3}{4}}=27

or

(x+3)34=27\displaystyle \frac{(x+3)^{3}}{4}=27?


If it's the first: (x+2)=2743\displaystyle (x+2)=27^{\frac{4}{3}}

x=27432\displaystyle x=27^{\frac{4}{3}}-2


If it's the second: (x+2)3=108\displaystyle (x+2)^{3}=108

(x+2)=(108)13\displaystyle (x+2)=(108)^{\frac{1}{3}}

x=(108)132\displaystyle x=(108)^{\frac{1}{3}}-2
 
It was the first one and thanks! I didn't even think about doing it that way. And sorry bout the equation, couldn't think of another way to write it, lol.
 
Centara said:
couldn't think of another way to write it
Use grouping symbols, such as:

. . . . .(x + 2)^(3/4) = 27

...as opposed to:

. . . . .[(x + 2)^3] / 4 = 27

Then your meaning is clear.

Thank you.

Eliz.
 
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