Exponential Integrals

[Ian McPherson]

(Integral sign e^4x-3/e^x/2)
You can rearrange the second term to make it e^4x - 3e^-x/2
However, I'm confused which of the terms to use to find u and du. Would it be the first? so U = 4x and du = 4? but then what do i do about the second term?

 

[srmichael]

(Integral sign e^4x-3/e^x/2)
You can rearrange the second term to make it e^4x - 3e^-x/2
However, I'm confused which of the terms to use to find u and du. Would it be the first? so U = 4x and du = 4? but then what do i do about the second term?

You take the integral of each term separately then combine them at the end with the dreaded "+ C" attached.