Exponential Growth Model?

justan4cat

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May 23, 2010
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I have a word problem and I'm totally lost from beginning to end. The instructions are to use the exponential growth model: P(t)=P[sub:2azos5y7]0[/sub:2azos5y7]e[sup:2azos5y7]kt[/sup:2azos5y7]

How long will it take for the population of a certain country to tripple if it's annual growth rate is 2.5%? (round to the nearest year).
 
\(\displaystyle P(t) \ = \ P_0e^{kt}, \ P(t) \ = \ P_0e^{.025t}\)

\(\displaystyle Now, \ if \ the \ population \ triples, \ then \ P(t) \ = \ 3P_0\)

\(\displaystyle hence, \ 3P_0 \ = \ P_0e^{.025t}\)

\(\displaystyle Therefore, \ can \ you \ now \ continue?\)
 
There are several things I don't understand about this problem.
Number one: What is the "e" represent? Is it a variable?
Number two: I'm looking at all the formulas for logarithms, and I don't understand what to do with the "0" after the P. Is it like a "log[sub:2m8ohayb]a[/sub:2m8ohayb]"?

I'm probably making this harder than it needs to be. I've been at this for almost 12 hours. I'm really struggling.
 
'e' is Euler's Number. It is a constant, just like pi, and has a value of 2.718... you can read about about it at http://mathforum.org/dr.math/faq/faq.e.html

You won't typically use the number in calculations, but instead as part of a "natural logarithm", which is Log[sub:3om6s84d]e[/sub:3om6s84d], typically written as LN.

P[sub:3om6s84d]0[/sub:3om6s84d] is a constant as well, in this case the starting population. Because your problem doesn't have a specific value for the population, you can just use P[sub:3om6s84d]0[/sub:3om6s84d]. You could use any letter, and the 0 just means it's the initial value.

Now, your problem looks like this:
3*P[sub:3om6s84d]0[/sub:3om6s84d]=P[sub:3om6s84d]0[/sub:3om6s84d]*e[sup:3om6s84d].025t[/sup:3om6s84d]

t is the value you need to solve for. In order to solve for an unknown in an exponent, you need to rewrite this problem as a logarithm. Take the natural log of each side.

3*P[sub:3om6s84d]0[/sub:3om6s84d]=P[sub:3om6s84d]0[/sub:3om6s84d]*e[sup:3om6s84d].025t[/sup:3om6s84d]
3=e[sup:3om6s84d].025t[/sup:3om6s84d]
LN(3) = LN(e[sup:3om6s84d].025t[/sup:3om6s84d])

An exponent inside of a logarithm can be brought outside and multiplied by the logarithm (it's just a basic property of logs):
LN(3) = .025t * LN(e)

Can you solve it from here?
 
Ted,

Thank you for removing the offending posts and bring in civility.
 
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