SOLVED
B BigGlenntheHeavy Senior Member Joined Mar 8, 2009 Messages 1,577 Nov 6, 2009 #2 Re: Exponential Growth and Decay: Deadly Virus! P(t) = Cekt, P(0) = 1000 = Cek(0) = C\displaystyle P(t) \ = \ Ce^{kt}, \ P(0) \ = \ 1000 \ = \ Ce^{k(0)} \ = \ CP(t) = Cekt, P(0) = 1000 = Cek(0) = C P(t) = 1000ekt, P(24) = 3 = 1000e24k\displaystyle P(t) \ = \ 1000e^{kt}, \ P(24) \ = \ 3 \ = \ 1000e^{24k}P(t) = 1000ekt, P(24) = 3 = 1000e24k \(\displaystyle k \ = \ ln(3/1000)^{1/24} \ \implire \ P(t) \ = \ 1000(3/1000)^{t/24}\) You should be able to take it from here.\displaystyle You \ should \ be \ able \ to \ take \ it \ from \ here.You should be able to take it from here.
Re: Exponential Growth and Decay: Deadly Virus! P(t) = Cekt, P(0) = 1000 = Cek(0) = C\displaystyle P(t) \ = \ Ce^{kt}, \ P(0) \ = \ 1000 \ = \ Ce^{k(0)} \ = \ CP(t) = Cekt, P(0) = 1000 = Cek(0) = C P(t) = 1000ekt, P(24) = 3 = 1000e24k\displaystyle P(t) \ = \ 1000e^{kt}, \ P(24) \ = \ 3 \ = \ 1000e^{24k}P(t) = 1000ekt, P(24) = 3 = 1000e24k \(\displaystyle k \ = \ ln(3/1000)^{1/24} \ \implire \ P(t) \ = \ 1000(3/1000)^{t/24}\) You should be able to take it from here.\displaystyle You \ should \ be \ able \ to \ take \ it \ from \ here.You should be able to take it from here.